6a^2+18a-7=-7

Solution for 6a^2+18a-7=-7 equation:

6a^2+18a-7=-7

We move all terms to the left:

6a^2+18a-7-(-7)=0

We add all the numbers together, and all the variables

6a^2+18a=0

a = 6; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·6·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*6}=\frac{-36}{12}
=-3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*6}=\frac{0}{12}
=0
$